Problem Statement
A minimal cut of a graph is a minimal set of vertices whose removal disconnects the graph. Let $c(n)$ be the maximum number of minimal cuts a graph on $n$ vertices can have.
Does $c(n)^{1/n}\to \alpha$ for some $\alpha <2$?
Does $c(n)^{1/n}\to \alpha$ for some $\alpha <2$?
Categories:
Graph Theory
Progress
Asked by Erdős and Nešetřil, who also ask whether $c(3m+2)=3^m$. Seymour observed that $c(3m+2)\geq 3^m$, as seen by the graph of $m$ independent paths of length $4$ joining two vertices.Solved by Bradač [Br24], who proved that $\alpha=\lim c(n)^{1/n}$ exists and\[\alpha \leq 2^{H(1/3)}=1.8899\cdots,\]where $H(\cdot)$ is the binary entropy function. Seymour's construction proves that $\alpha\geq 3^{1/3}=1.442\cdots$. Bradač conjectures that this lower bound is the true value of $\alpha$.
Source: erdosproblems.com/150 | Last verified: January 13, 2026